
Part of series: PS
2532 BOJ
문제
접근
처음에 dp로 해결하려 했다가, 시간초과를 받고 이분 탐색을 이용한 LIS 풀이로 바꾸었다.
코드
#include <algorithm>
#include <bits/stdc++.h>
#include <utility>
using namespace std;
typedef long long ll;
typedef unsigned long long ull;
typedef pair<ll, ll> pll;
typedef pair<ull, ull> pull;
typedef const ll cll;
typedef queue<ll> qll;
typedef queue<pll> qpll;
typedef priority_queue<ll> pqll;
typedef priority_queue<pll> pqpll;
typedef vector<ll> vll;
typedef vector<pll> vpll;
typedef vector<vll> vvll;
typedef vector<vpll> vvpll;
#define FOR1(a, A) for (ll a = 0; a < A; ++a)
#define FOR2(a, b, A, B) \
for (ll a = 0; a < A; ++a) \
for (ll b = 0; b < B; ++b)
cll N = 5e5, L = 1e9, R = 1e9;
ll n;
vpll animals;
bool isPrey(pll &predator, pll &prey) {
ll l = predator.first, r = predator.second, _l = prey.first, _r = prey.second;
if (l == _l && _l == _r) {
return false;
} else if (l <= _l && _r <= r) {
return true;
} else {
return false;
}
}
bool comp0(pll a, pll b) {
if (a.first != b.first) {
return a.first < b.first;
} else {
return a.second > b.second;
}
}
bool comp1(pll a, pll b) { return isPrey(a, b); }
int main(void) {
ios::sync_with_stdio(false);
cin.tie(NULL);
cout.tie(NULL);
cin >> n;
for (ll l, r, idx, i = 0; i < n; ++i) {
cin >> idx >> l >> r;
animals.emplace_back(make_pair(l, r));
}
sort(animals.begin(), animals.end());
animals.erase(unique(animals.begin(), animals.end()), animals.end());
sort(animals.begin(), animals.end(), comp0);
ll result = 0;
vpll lis = {animals[0]};
for (ll i = 1; i < n; ++i) {
auto it = lower_bound(lis.begin(), lis.end(), animals[i], comp1);
if (it == lis.end()) {
lis.emplace_back(animals[i]);
} else {
*it = animals[i];
}
}
cout << lis.size() << "\n";
return 0;
}